Toot

Written by Jonathan Kamens on 2025-01-21 at 05:12

@jztusk @jztusk Yes, you win the 🏆 for the first and correct answer.

And although it hadn't occurred to me, I actually think you're right that a positive lookahead assertion would work here in stead of the loop. I think I could have done:

$value =~ s/\n(?=[^ \t])/\n /g;

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