Toot

Written by stefanct on 2024-08-10 at 16:14

Playing around with #C23 stuff and got surprised by this not working…

void func(void);

typedef typeof(func) func_type;

Since a function name is neither an expression nor a type name, it's not supported as operand to typeof (not sure that's all), fair enough but why? @AaronBallman @thephd

I'd have used it to have the prototypes of a library functions in a header and use the typedef within the "private" .c only. This would avoid the alternative of duplicating the prototype within the typedef.

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