Toot

Written by Benoît Régent-Kloeckner on 2024-08-09 at 10:00

@sstadnicki mathematician here, not answering your question but making a tangential point. I would advise to find what really makes sense to be added, expressed as a function f of the value, then use

f^{-1}( t f(A) + (1-t) f(B) )

For example, if your values are side-length of a 2D figure, usually it will feel smoother to have the area be interpolated linearly: you then take f(x)=x^2 and thus interpolate by

√( tA^2 + (1-t)B^2 )

or

√( B^2 + t (A^2 - B^2) )

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